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Question by Sreenivasa Kumar Majji

 
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What will happen if you compile/run this code?
1: public class Q10
2: {
3: public static void main(String[] args)
4: {
5: int i = 10;
6: int j = 10;
7: boolean b = false;
8:
9: if( b = i == j)
10: System.out.println("True");
11: else
12: System.out.println("False");
13: }
14: }
A) Compilation error at line 9 .
B) Runtime error exception at line 9.
C) Prints "True".
D) Prints "False".

Answer : C
Explanation : Conditional operators have high precedence than assignment operator.
My question is : How it's works?
Thank You.
 
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The explanation says it all. Conditional operators have higher precedence over assignment. Therefore in the expression
if( b = i == j)
i==j is evaluated before b=i.
i==j is true then b is assigned true & then true is printed out.

Originally posted by SteffySY Sing:
What will happen if you compile/run this code?
1: public class Q10
2: {
3: public static void main(String[] args)
4: {
5: int i = 10;
6: int j = 10;
7: boolean b = false;
8:
9: if( b = i == j)
10: System.out.println("True");
11: else
12: System.out.println("False");
13: }
14: }
A) Compilation error at line 9 .
B) Runtime error exception at line 9.
C) Prints "True".
D) Prints "False".

Answer : C
Explanation : Conditional operators have high precedence than assignment operator.
My question is : How it's works?
Thank You.


 
sing
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Dear Roopa,
I understand your explanation. Thank you. You have helped me 2 questions.
Steffy

[This message has been edited by SteffySY Sing (edited December 05, 2001).]
 
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