RequestDispatcher question

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posted 16 years ago

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I have the following JSP and a html file, forw.html with text, "This is static content"

When I request the JSP, I get an illegal state exception. The stack trace is copied. If I use forw.jsp(when getting the request dispatcher) which has the same contents as forw.html, the code works (The browser displays "This is static content"). I looked at the API and did not find anything, Can someone explain this.

Source of the question: HFSJ Final Mock, based on Question 22

java.lang.IllegalStateException: getOutputStream() has already been called for this response
org.apache.coyote.tomcat5.CoyoteResponse.getWriter(CoyoteResponse.java:599)
org.apache.coyote.tomcat5.CoyoteResponseFacade.getWriter(CoyoteResponseFacade.java:163)
org.apache.jasper.runtime.JspWriterImpl.initOut(JspWriterImpl.java:122)
org.apache.jasper.runtime.JspWriterImpl.flushBuffer(JspWriterImpl.java:115)
org.apache.jasper.runtime.PageContextImpl.release(PageContextImpl.java:190)
org.apache.jasper.runtime.JspFactoryImpl.internalReleasePageContext(JspFactoryImpl.java:115)
org.apache.jasper.runtime.JspFactoryImpl.releasePageContext(JspFactoryImpl.java:75)
org.apache.jsp.forward4_jsp._jspService(forward4_jsp.java:61)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

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