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Greenhorn
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Consider the code fragment below:

outer: for( int i = 1; i <3; i++ )
{ inner: for( j = 1; j < 3; j++ )
{ if( j==2 )
continue outer;
System.out.println( "i = " +i ", j = " + j );
}
}

Which of the following would be printed to standard output?
a) i = 1, j = 1
b) i = 1, j = 2
c) i = 1, j = 3
d) i = 2, j = 1
e) i = 2, j = 2
f) i = 2, j = 3
g) i = 3, j = 1
h) i = 3, j = 2
 
Desperado
Posts: 3226
5
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I recommend that the best (?) way of answering this question is to get a piece of paper and try to execute the code in one's head and write down the results as they are "printed". You need to keep track of both variables at the same time so that's where the piece of paper (which you will have in the real exam) comes in handy. Please give it a try and report back any inconsistency that you may find in your results when compared to the ones given.
Also remember the diference between <CODE>break</CODE> and <CODE>continue</CODE>
 
Ranch Hand
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I think the ans. will be i=1,j=1 and i=2,j=1 .
Please correct me if i am wrong.
First i=1,j=1 and 'if' condition is not satisfied . Then j=2 and outer loop is continued.Hence i=2 and j again initializes thus j=1.Then again j=2 ,outer loop continues .But this time the outer loop condition i<3 is not satisfied,hence only the above 2 lines are printed.
 
Greenhorn
Posts: 23
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You are right Udayan. I compiled and checked.
 
Don't get me started about those stupid light bulbs.
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