why is it so??

[Anonymous]

i came across these 2 questions in a mock test.the first one is:
boolean flag = false;
if (flag = true) {
System.out.println("true");
} else {
System.out.println("false");
}
the answer to this is :true is printed .
the 2nd one is:
Which of the following are acceptable to the Java compiler:
A:if (2 == 3) System.out.println("Hi");
B:if (2 = 3) System.out.println("Hi");
C:if (true) System.out.println("Hi");
D:if (2 != 3) System.out.println("Hi");
E:if (aString.equals("hello")) System.out.println("Hi");
Select all correct answers.
The answer is A,C,D,E
if (flag=true)can be accepted by the compiler as in 1st question,why not if(2=3) is acceptable.can anyone tell me why is this so please.

[Tony Alicea]

"If (flag=true)can be accepted by the compiler as in 1st question,why not if(2=3) is acceptable.can anyone tell me why is this so please."
Because the only primitive value allowed inside the "()" is boolean.
The result of ( i=j ) in
int i=2;
int j=3;
if (i=j){}
is an int.
but the result of
flag=true
is boolean so it's OK.

[This message has been edited by Tony Alicea (edited February 09, 2000).]