strings

[Anonymous]

Hey i have a very silly doubt......
String s="abc";
String s1=new String("abc");
if (s1.equals(s))
System.out.println("true")
else
System.out.println("false")
also
String s ="abc";
s=s+"def";
System.out.println(s);
What will the value of s be now???
Help someone

[javaguru]

The answer to first question will be "true".The string class overrides the equals method it inherites from 'Object' class so equals in String provides a deep comparison which is a chracter by character comparison(unlike== which is shallow comparison).
The value of string s will will be "abcdef" in your 2nd question.The + operator is overloaded by the Java Language which allows string concatenation to be done in this manner.

[Tony Alicea]

<PRE>String s ="abc";
s=s+"def";
System.out.println(s);
What will the value of s be now???
</PRE>
What happens here is that s now denotes a different String object ("abcdef") from the one it denoted before ("abc").
s is not a String but a String object reference.

[Anonymous]

hi,
String s ="abc";
s=s+"def";
System.out.println(s);
What will the value of s be now???
instead of saying s=s+"def"; if u said
String s ="abc";
s+"def";
System.out.println(s);
then the value of s still remains "abc". This is because the new string formed is not assigned to any reference of type string and is hence "lost" to be garbage collected.
Rahul.

[This message has been edited by rahul_mkar (edited June 08, 2000).]