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Sorry for the misprint of my previous question

 
Greenhorn
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He is the question again,
Given the following variables which of the following lines will compile without error?
String s = "Hello";
long l = 99;
double d = 1.11;
int i = 1;
int j = 0;

1) j= i << s;
2) j= i << j;
3) j=i << d;
4) j=i << l;
The correct answer is 2 & 4.I thought that it was only 2.Can anyone explain why it 4 too?Does'nt it apply arithmetic promtion here?Please help me.
Thanks
Sangi

[This message has been edited by Jim Yingst (edited June 15, 2000).]
 
Wanderer
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No, normal aritmetic promotion does not apply to the shift operators. They have their own rules, which are given here:
<blockquote>Binary numeric promotion (�5.6.2) is not performed on the operands; rather, unary numeric promotion (�5.6.1) is performed on each operand separately. The type of the shift expression is the promoted type of the left-hand operand.</blockquote>
 
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