Passing arguments to method

[Anonymous]

Hi everyone,
I thought the answer is sb1 is "HelloThere"; sb2 is "HelloThere",but is wrong.
Could anyone kindly explain to me.
Thanks a lot.
Vic

 public class StrBufTest {
      public void method1(StringBuffer s1, StringBuffer s2){
         s1.append("There");
         s2 = s1;
      }
      public static void main(String[] args){
         StringBuffer sb1 = new StringBuffer("Hello");
         StringBuffer sb2 = new StringBuffer("Hello");
         StrBufTest sbt = new StrBufTest();
         sbt.method1(sb1, sb2);
         System.out.println("sb1 is " + sb1 + "\nsb2 is " + sb2);
      }
   }  

[I added UBB CODE tags to your source code to make it more readable. Please try to use them in the future - Ajith]

Answer is: sb1 is "HelloThere"; sb2 is "Hello".

[This message has been edited by Ajith Kallambella (edited September 05, 2000).]

[Shankar G]

This question has been already asked & answered, within in the past week -- plz. refer to the previous questions.

[Anonymous]

When a method is called with parameters, the parameters is the copy of the real parameters. In the test, the refrence s1 and reference s2 is the copy of sb1 and sb2. Doublelessly, the first object is appended which is referenced by s1 and also by sb1. Though s2 is assigned with s1 in the method, the s2 really referencing the first object which appended, the sb2 still referencing the second object which has not been updated.
Did i expain it clear?

[Anonymous]

Thanks very much Shankar and Yiqing. I got it.
Vik