Urgent Help from anyone

[bala_chocos]

hi guys
please explain how the answer is correct
QUESTION : 6
Consider the following class
1. class Tester {
2. void test (int i) { System.out.println ("int version"); }
3. void test (String s) { System.out.println ("String version"); }
4.
5. public static void main (String args[]) {
6. Tester c = new Tester ();
7. char ch = 'p';
8. c.test (ch);
9. }
10. }
ans print "int version"

[Anonymous]

it's simple.
If u know abt automatic conversion, char field can be assigned to int field (Widening case). so java converts char to int and called appropriate method.
Thanks
Ashish

[Paul A]

Because char is also an integral data type (which does not take -ive integers). When compiler tries to lookup a test method that takes a char, it doesn't find one so it looks for a closest (but eligible!) match, it finds the int version. So it promotes the char to int and calls that method!
HTH,
Paul.
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