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Posts: 173
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<if catch throws a new exception, not mentioned with any throws clause, then it will not be handled. The>
reason mainly being that
1)it was not declared in throws
2)there is no mention in try block to handle it.
Plz confirm!

public class divby0{
public void div() throws ArithmeticException{
int n1= 2;
int n2= 0;
catch ( ArithmeticException e)
System.out.println("i will catch this exception");throw new RuntimeException ();
System.out.println("finally...going out");
System.out.println("over to roger");
Posts: 26
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Here you need a nested try-catch, in Outer try block you need to handle the exception thrown by the statement
throw new RuntimeException ();
Hope this helps.
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