Package and Overriding

[Bin Zhao]

Question:
Consider the following class definition:
public class Parent {
final void zzz() { }
}
Which of the following methods may appear in a subclass of Parent, when the subclass is in a different package from Parent? Choose all correct options.
A) void zzz() { }
B) void zzz(int j) { }
C) final void zzz(float f) { }
D) public final void zzz(double d) { }
I choose A,B,C,D
but the anwser said I am wrong.
Who can give correct anwser to this question?

[Bin Zhao]

BTW,the anwser to the above question is B,C,D.

[Edy Yu]

Cus the subclass is in the different package and final void zzz() doesn't have any modifier(means it's only avaible in the same package)

[Edy Yu]

and also since it's final, it can't be overiddend in the subclass

[Bin Zhao]

But I tried the following code and it compiles well
Sub.java
import abc.Parent;
public class Sub extends Parent {
void zzz() { }
// void zzz(int j) { }
//final void zzz(float f) { }
//public final void zzz(double d) { }
}
Parent.java in another package abc
package abc;
public class Parent {
final void zzz() { }
}
So I think anwser A is right since the zzz(0 method in Parent class has default access,it can not be seen in other packages.
So the Sub class can define zzz() method freely.
This is just like private method.The subclass can define a method with the same signature and return type as the private method in superclass.

[Edy Yu]

Are you sure you testes right?
I tested your code which gave me a compilation error.

[Bin Zhao]

I am sure.
What error did you get?
you have to put Parent.java in a dirctory named abc.
For example:
Parent.java -->c:\java\abc
Sub.java -->c:\java
Then you can compile Sub.java without error.