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Question from Majji's paper

 
Greenhorn
Posts: 6
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The following code will give
1: Byte b1 = new Byte("127");
2:
3: if(b1.toString() == b1.toString())
4: System.out.println("True");
5: else
6: System.out.println("False");
A) Compilation error, toString() is not avialable for Byte.
B) Prints "True".
C) Prints "False".

The answer given is C(prints false).
I think b is correct answer. Can anyone please guide?
 
Ranch Hand
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This is a common error. The toString method returns a new string, so when you use the == it looks to see if they are the same object, not thier content. Since they are two different objects since both were created with the new keyword, they will evalute to false. If you did equals() then it would be true since this looks at the contents of the String object.
Bill
 
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