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Q'tion from Majji's paper

 
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code//
The following code will print
1: Double a = new Double(Double.NaN);
2: Double b = new Double(Double.NaN);
3:
4: if( Double.NaN == Double.NaN )
5: System.out.println("True");
6: else
7: System.out.println("False");
8:
9: if( a.equals(b) )
10: System.out.println("True");
11: else
12: System.out.println("False");
A) True
True

B) True
False

C) False
True

D) False
False
The answer given is c) (False and True).
can anyone explain me how c) is the correct answer.
Thanx.
 
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From the API:


Note that in most cases, for two instances of class Double, d1 and d2, the value of d1.equals(d2) is true if and only if
d1.doubleValue() == d2.doubleValue()
also has the value true. However, there are two exceptions:
If d1 and d2 both represent Double.NaN, then the equals method returns true, even though Double.NaN==Double.NaN has the value false.

If d1 represents +0.0 while d2 represents -0.0, or vice versa, the equal test has the value false, even though +0.0==-0.0 has the value true. This allows hashtables to operate properly.


So this is a special case. Also pay attention to 0.0 and -0.0 as this is the opposite of NaN.
Bill
 
ashwini srinivasan
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Thanks a lot bill for nice explation.
regards
Ashwini.
 
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