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inner class question from HUNT

 
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Examine the following code which includes an inner class:

public final class Test4 implements A {
class Inner {
void test() {
if (Test4.this.flag); {
sample();
}
}
}
private boolean flag = false;
public void sample() {
System.out.println("Sample");
}
public Test4() {
(new Inner()).test();
}
public static void main(String args []) {
new Test4();
}
}

What is the result:
A. Prints out "Sample"
B. Program produces no output but terminates correctly.
C. Program does not terminate.
D. The program will not compile
Select the most appropriate answer.
//I THOUGHT THIS SHOULD NOT COMPILE SINCE THE INNER CLASS IS CREATED INCORRECTLY (new Inner()), without creating an instance of the outer class ???

 
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The inner class is created correctly since you inside of the outer class, you don't need to reference the outer class when you create the inner class.
Now it still won't compile becuase it says it "implements A" and A is not defined anywhere or ever mentioned in the question, so you don't know what methods A has that you need to implement. However, I don't think that is what they are getting at with this question, so assume that A compiles fine, is in the same package and only has one method sample(). Now what is the answer?
Bill
 
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IF v go according to Bill, then the output should b "A" ie prints "Sample". This is because of the semicolon after the if statement. So even though if condition is false it will execute sample(). Correct me if i m wrong.
 
bill bozeman
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That's right umang. That little semicolon is easy to miss too.
Bill
 
With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.
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