Kindly Explain

[Morgan Subram]

public class TestThis{
public static void main(String args[]){
System.out.println(1 + 2 + "Strange");
System.out.println("Strange" + 1 + 2);
}
}
After compiling this
when you run this
The first output is 3Strange
why is the second output Strange12 rather than Strange3 ?

[Ananda Kashyap]

I think, it's because, arithmatic expression starts from left side ( if the operators are same) and for the first example it already added both the numbers and then got the String and added it that way. But in case of the 2nd, since the 1st member is String it took everything as String.
Guys please give your more technical explanation.
Ananda
I am new to Java, so any advice is welcome.

[Axl Rose]

Yes, Ananda , you are right
starting from left to right , java evaluate its expressions.
so, 1+2+"strange" will take the following steps:
1- take the first expression 1, and the second one , 2, then add them, giving 3
2- take 3, and the next expression which is a string, and add them, remember now this is not the arithmatic addition, this is the string concatenation +, becuase we have a string, so a new object is created with of type string and have the value "3strange"
if you follow the same logic ,the second statement should make sense.
hope this help