Terenary operator

[vikas singh]

Pl. suggest :
The problem is with terenaray operator.When I am putting
66 as value-1 & '65' as value-2 ,I am getting comp.'n error saying
invalid character constant, whereas if I am putting '6' as value-2,
it get compiled.
class Operator31
{
public static void main(String[] args)
{
int x=1;
// Lna:System.out.println((x>3 )?66:'65');//compErr:Invalid
//character constant.-'65'
Lnb: System.out.println((x>3 )?66:'6');
//compiling (x>3?66:'6');o/p=6.
}
}// end of class Opeartor31
I am clueless. . .
Thanks,
Vikas

[S Dave]

were u expecting an 'A' there?
'65' is not a valid character. if u say char c = 65; it is valid and will print an 'A' because the integer value 65 represents 'A'. in single quotes u can have a single character. 65 is not a character.

[Sujit Kurtadikar]

This can be expalined as,
char c1 = '65'; //invalid
char c2 ='6'; //valid
char only takes unicode datatype, '65' is not basic character in Unicode (or ASCII) character set. It is combination of to charcters '6' and '5' so it gives error.
char c1 = 65; Same can be represented as,
char c1 ='A';
char c1 ='\u0041'; //hex equivalent of decimal 65

[vikas singh]

thanx sweekriti & sujit,
could you pl. further provide me some links from where
i can get details about unicode & ascii.
regards,
vikas