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About packages and complications - total confusion

 
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A question from JQ+
Consider following two classes:
//in file A.java
package p1;
public class A
{
protected int i = 10;
public int getI() { return i; }
}
//in file B.java
package p2;
import p1.*;
public class B extends p1.A
{
public void process(A a)
{
a.i = a.i*2;
}
public static void main(String[] args)
{
A a = new B();
B b = new B();
b.process(a);
System.out.println( a.getI() );
}
}
What will be the output of compiling and running class B ?
Answers : Will print 10; 20 ; not compile ; runtime excep
Pls spare time to explain concept behind it --- THANX
 
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This in my opinion is a tough one. I got this wrong the first time through.
The answer is that it won't compile.
Reason:
While "i" is protected in Class A, so you can access in the same package or with a subclass of A, you would think that you can access it in class B just fine. Well you can, but in this example, they are not accessing it in class B directly, they are using a reference of class A to get to "i". This would work if they were in the same package, but since they are not, the reference variable "a", can't see "i".
Confusing, and I don't know if I explained it well. So maybe someone can try to explain it better.
Bill
 
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i tried many interesting variations on this code and so should you.
well, what do i explain... your questions should be more specific.
1)there is runtime polymorphism only regd. over-ridden methods.
2)inside a method a call to another variable and method is supercededed by the implicit this.
3) blah blah blah...
i suggest you copy the method getI() into B too, and then see the result.
 
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That's true , it's only available inside it's own package and to sublcasses , I believe that you can get access to i though the reference of B but not though A.
 
Anshuman Acharya
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uh oh! this is a package problem... i just saved time by putting it all in one package! sorry....
here's the answer....
if c extends b and b extends a, and a has a protected variable i, and they are in different packages-
b can call its own i.
b can call its sub-class' c's i,
but it can't call a's i.
 
Greenhorn
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Ah the answer to that through me off for a bit and I had to go try this out.
I discovered that while i is protected, b cant access i located in an A object but if you pass a B into a method of A's A can access b.i
such as this:

for some reason I kept thinking that since it is protected that a subclass could access a parent objects protected member, but really the subclass can contain an instance of a protected member but it cant access a parents parents protected member.
Did I state that correctly?

[This message has been edited by Lee Clarke (edited February 02, 2001).]
[This message has been edited by Lee Clarke (edited February 02, 2001).]
 
Shailendra Guggali
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Thanx Bill and everyone
i think i understand it now
shailendra
 
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Hi,
I have modified B.java file and want to access only a.i it gives me compiler error saying "I can't access the protected i". Is it because, protected variables can't be accesed by instantiation?
Ananda.

package p2;
import p1.*;
public class B extends p1.A {
public static void main(String[] args) {
A a = new A();
System.out.println( a.i); // Compiler error
System.out.println( getI()); // OK, returns 10
}
}
 
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