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operators

 
Greenhorn
Posts: 18
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what will happen if you compile/run this code?
public class Q10
{
public static void main(String[] args)
{
int i = 10;
int j = 10;
boolean b = false;
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");
}
}
Answer says True... Please explain!
 
Ranch Hand
Posts: 96
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Hi! Sai
In the statement
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");

due to precedence of operators '==' has a higher precedence than '=' and so the statement can be read as b = (i==j);
i == j will be true and this gets assigned to the boolean b
hence the answer is 'true'.
Hope this helps.
Latha

Originally posted by Sai Ram9:
what will happen if you compile/run this code?
public class Q10
{
public static void main(String[] args)
{
int i = 10;
int j = 10;
boolean b = false;
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");
}
}
Answer says True... Please explain!


 
Sai Ram9
Greenhorn
Posts: 18
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Thanks latha. good and clear explanation.
 
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