Please , what is the answer to this question

[kaffo lekan]

class Class1 {
static int i=0;
public static void main(String args[]) {
for(int j=0;j<4;j++) {
i += j;
}
System.out.println(i);
}
}
What is the output of the program above?
1. 0
2. 4
3. 6
4. 8
5
none, the compiler will error because i is not a String in the print statement

[Wasim Ahmed]

The answer will be 6.
How ? follow this
i=0 , j=0 Result= 0
i=0 j= 1 1
i=1 = 2 3
i=3 3 6
loop exit after j = 4(4<4).
Hope it help.

[Swati Jambhale]

Hello Friend
This code doesnt gives a error.
System.out returns a reference of type PrintStream. PrintStream has number of overloaded println() method, one of which takes int as a argument. So your code should work.

[shashank hiwarkar1]

Hi Wasim,
You are Correct, Code will not give any error, with o/p as 6

shashank

[Angela Poynton]

For future reference with a question like that the best way to get the answer is to compile and run the program yourself. If you get a result you do not expect you can then say "Why do I get this result?"