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reply to srini

 
Greenhorn
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import java.applet.*;
2: import java.awt.*;
3:
4: public class Q20 extends Applet
5: {
6: Button okButton = new Button("Ok");
7:
8: public void init()
9: {
10: setLayout(new BorderLayout());
11:
12: add("South", okButton);
13: add("North", okButton);
14: add("East", okButton);
15: add("West", okButton);
16: add("Center", okButon);
17:
18: setSize(300,300);
19: }
20: }
The above Applet will display
A) Five Buttons with label "Ok" at Top, Bottom, Right, Left and Center of the Applet.
B) Only one Button with label "Ok" at the Top of the Applet.
C) Only one Button with label "Ok" at the Bottom of the applet.
D) Only one Button with label "Ok" at the Center of the Applet.

The answer for this is given to be B.
I thought the answer is A
Can someone explain ?
Thanks,
Srini
<reply>
The answer B is correct because u r not taking in consideration that u r playing with same button=OKButton.Hence u r superimposing same button with other diff buttons & inly the last 1 wiil be same.
Hope u r clear.
deepak
 
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I think the answer should be D,
since the default FlowLayout was changed to BorderLayout.
stevie
 
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hi
can anyone throw any light on the above question.
finally why the answer should be b ,
i understood it cannot be 'a'n bcause same button is used
and no new button is created.
but why button will be displayed in north and not any other
part of the applet (south , east , west)
can anyone xplain the above
 
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b wrong and d is the correct choice,here u are allocating the memory to the button just once and u are adding that button to all the direction's, threfore the button addded in last position will be displayed ,as last statemnt add's the button in the center, therefore the button in the center become's visible and it take's the entire frame.
 
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