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# division by zero

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Hi, I have a question about division by zero. RHE has an example that
double d = 10.0d/0.0d;
if(d==double.POSITIVE_INFINITY)
//whatever...
Why is ArithmaticException not thrown? Is it because it's a floating type and not integer type?

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That's exactly right, Cameron. I believe that values for infinity and negative infinity are a part of the floating-point standard that Java uses, IEEE 754. Other aspects of java.lang.Double might jog your imagination on this topic.
Also, I thought I'd point out that in the code sample you gave, you could also use java.lang.Double's static method isInfinite():

(N.B., isInfinite() returns true if "d" equals Double.NEGATIVE_INFINITY or Double.POSITIVE_INFINITY.)
HTH,
Art
[This message has been edited by Art Metzer (edited May 04, 2001).]

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Hi Cameron,
I f you do division by Zero with integral type (i.e byte, short,int,long)then Arithmatic Exception will be thrown.But if you do division by zero with floating point it will not throw Arithmatic Exception.Because Java makers trust that +infinity & -infinity exist.So they put facility of showing +ve & -ve infinity in Java but they select float & double to show infinity.Because float & double have big range then integral types.
This is what i think.May be i am wrong.Confirm it before accepting.
Hassan.

Greenhorn
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hi
u have said double.POSITIVE_INFINITY
i think u should write d in caps i.e. Double.POSITIVE_INFINITY
abhijit lodha :-)

Cameron Park
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Thanks! double doesn't have any fields. Hehehe

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