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public class AQuestion
{
public static void main(String args[])
{
System.out.println("Before Try");
try
{
}
catch(java.io.IOException t)
{
System.out.println("Inside Catch");
}
System.out.println("At the End");
}
}
a. Compiler error complaining about the catch block where no IOException object can ever be thrown.
b. Compiler error - IOException not found. It must be imported in the first line of the code.
c. No compiler error. The lines "Before Try" and "At the end" are printed on the screen.
I know the ans ia a. But I don't understand why?Can somebody explain me?
Thanks,
Ash
 
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In the try block you have to write the code
which throws an IOException otherwise it gives
compiler error
 
Kishore Pamu
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In the try block you have to write the code
which throws an IOException otherwise it gives
compiler error.
 
Consider Paul's rocket mass heater.
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