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Static method

 
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Another question. I thought the follow code would not compile because i is non-static, which cannot be accessed by static change_i?
Thank you.
class StaticTest3
{
int i = 0;
public static void main(String[] args)
{
int i = 1;
change_i(i);
System.out.println(i);
}
public static void change_i(int i)
{
i=2;
i*=2;
}
}
 
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The int i in main is a local variable, not the instance variable int i.
 
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i is non-static, which can only be access by instance(object).U can not access i by static method i.e main()
Hassan.
 
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I think, there is a hiding of instance variable in this code.if you change int i to int j, it will be clear.


[This message has been edited by swati bannore (edited July 16, 2001).]
 
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