Thread q from m. green

[sam pitt]

The following is from marcus green test 1

public class MyClass extends Thread
{
        static String sName = "vandeleur";
        public static void main(String argv[])
        {        
          MyClass t = new MyClass();
          t.piggy(sName);
;    
          System.out.println(sName);
        }
        public void piggy(String sName)
        {
           sName = sName + " wiggy";
           start()
        }
        public void run()
        {                
           for(int i=0;i  <  4; i++)
           {
                sName = sName + " " + i;  
           }
        }
}

When executed It prints "vandeleur". Why is that so ? I thought it should have been something like "vandeleur 0 1 2 3" because run() gets executed when start() is called .. right ?
-Sam

[sam pitt]

Never mind ranchers.. I found a similar thread here
http://www.javaranch.com/ubb/Forum24/HTML/010591.html
Thanks
Sam

[Glen Tanner]

Yep, run gets executed, but remember that two threads are running. main() prints before run() finishes.
That is:
main() calls piggy(),
piggy() starts the new thread and returns,
main() prints, (what it has for sName..."vandeleur")
then run finishes executing.
(I think...I could be wrong!)
Oops, sorry I was too slow.....

[This message has been edited by Glen Tanner (edited July 30, 2001).]