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protected variable?

 
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Consider following two classes:


What will be the output of compiling and running class B ?
Answer : It will compile
According to me it should compile because as 'i' is declared as protected in class A, Class B can access this variable?
Please explain
Sonir
 
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It will give compiler error because i is protected. And you can access the code in subclass only by subclass reference. You can't access from superclass reference.
 
sonir shah
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Arathi
I am still not clear with the concept, could you just explain me in a bit detail..If possible with examples?
Sonir
 
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are you sure you have the right code here:
{a.i = a.i*2;} is this ok ? can u verify this again. this assignment itself looks vague. we are not even discussing protected or etc. just the assignment. the RHS looks like some typo error.

Originally posted by sonir shah:
Consider following two classes:


What will be the output of compiling and running class B ?
Answer : It will compile
According to me it should compile because as 'i' is declared as protected in class A, Class B can access this variable?
Please explain
Sonir

 
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Originally posted by mark stone:
are you sure you have the right code here:
{a.i = a.i*2;} is this ok ? can u verify this again. this assignment itself looks vague. we are not even discussing protected or etc. just the assignment. the RHS looks like some typo error.



Why does this look vague to you? Even out of context, this assignement is just saying "take the member i in the object referenced by variable a, and multiply this by two, then store it back into the memory associated with data member i in the object referenced by variable a."
It's the same type of construct as
i = i*2.
Where are you confused?

Rob
[ January 17, 2002: Message edited by: Rob Ross ]
 
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Hi Sonir,
I think your orginial post about this code is here. Titled
"Why isn't compiling" a few people have answered your question. And I think the answer are pretty good. If you write another class called C.java and put it in the same package as A.java you'll see it can gain access (just like what Prashanth menon and Rob Ross
say).
hope this helps.
Bob
[ January 17, 2002: Message edited by: Bob Tai ]
[ January 17, 2002: Message edited by: Bob Tai ]
 
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