invoking methods - help!!!!!

[Rob Petterson]

What happens when you compile and run the following code?
public class Test
{
public void myMethod(Object o)
{
system.out.println("My Object");
}
public void myMethod(String s)
{
system.out.println("My String");
}
public static void main(String args[])
{
Test t = new Test();
t.myMethod(null);
}
}
// Why does it print "My String"??
// Is it because it is the more specific method in
// the hierachy tree??

[Valentin Crettaz]

// Why does it print "My String"??
// Is it because it is the more specific method in
// the hierachy tree??
That's exactly that !
You might want to have a look at JLS 15.12.2 Compile-Time Step 2: Determine Method Signature
and
JLS 15.12 Method Invocation Expression in Plain English

[Jose Botella]

Yes String parameter is more specific than Object.
Read about the whole process at JLS 15.12

[Rob Petterson]

Thanks for that. The JLS explains it well - cheers

[R K Singh]

http://www.javaranch.com/cgi-bin/ubb/ultimatebb.cgi?ubb=get_topic&f=24&t=012648
HTH