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JQ+ question

 
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..Shortened version
float f = 0.0f;
try
{
return f;
}
finally
{
f=10.0f
return f;
}
JQ+ says it will return 10.0. I guessed it wouldn't compile. What exactly happens to the first return f?.. where does it go??
 
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Did you compile the code?
What do you think is happening?
Brian
 
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finaly will always execute !
(with one exeption when you got System.exit() in your try or catch block)
-so your return statement in finaly block will overlay other return.
 
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i think it wont be compiled.because there is no catch block. right ?
 
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IntelliJ IDE Java
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andy,
nope, whenever there is a try block there must be either a catch block or a finally block or both. But if there is a finally block the catch block is not mandatory.
 
andy lau
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thanks.
but there is another question:
as the first return is not an error,so the method is terminated when the first return happen,right?
 
Valentin Crettaz
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nope, if a finally block is present, it will always be executed, whatever control-breaking statement you put in the try block. And here it turns out that the finally block contains a return statement. It is the latter that will return the control to the caller method.
[ April 12, 2002: Message edited by: Valentin Crettaz ]
 
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Val, not unless there is a System.exit() call in the try block.
 
Valentin Crettaz
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That's right Jay, I forgot to mention that one...
 
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