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Operators

 
Greenhorn
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Hi,
I have a question about this ...
int x =10++11;
I say, that this is a invalid statement, because the operator is applicated over the variable...
What do you know?
 
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Compile it and see - you'll find that this does not compile as the ++ operator has no variable to operate upon.
Corey
 
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if it's written as :
1) int x = 10+ +11;
It works ,the o/p is 21.
2)int x = 10 + +11;
It works ,the o/p is 21.

Is the positioning of space so important,pl.help clarify.
 
Corey McGlone
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Originally posted by geetha nagarajan:
if it's written as :
1) int x = 10+ +11;
It works ,the o/p is 21.
2)int x = 10 + +11;
It works ,the o/p is 21.

Is the positioning of space so important,pl.help clarify.


In this case, the space makes little difference as to where it is. The only thing that matters is that there is a space between the '+' signs. If they're together, they represent the increment operator in Java. If they're separate, they represent the addition operator.
Corey
 
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This may be helpful JLS 3.2


The longest possible translation is used at each step, even if the result does not ultimately make a correct program while another lexical translation would. Thus the input characters a--b are tokenized (�3.5) as a, --, b, which is not part of any grammatically correct program, even though the tokenization a, -, -, b could be part of a grammatically correct program.

 
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