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divide by zero: Not a compile time error

 
Ranch Hand
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Hi there:
Why divide by zero not a compile time error. I
always thought it was. but following code gives
run time exception:
 
mister krabs
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Because the compiler doesn't check for divide by zero.
 
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On Java 1.1.8 , I get a compiler error ("Arithmetic exception"). Does this not happen in later compilers?
 
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Its Arthmetic Exception ...not compiler error.
(tried on java 1.4)
 
Thomas Paul
mister krabs
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Originally posted by Ron Newman:
On Java 1.1.8 , I get a compiler error ("Arithmetic exception"). Does this not happen in later compilers?

If your compiler is throwing exceptions then you have serious problems.
 
Greenhorn
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Hello
public class divbyzero
{
public static void main(String args[])
{
int x=10;
int y=10/0;
System.out.println(y);
}
}
The java compiler dosent even care about the Values u havce assigned.This is taken care of at Run time .So the JVM throws a Runtime exception.
 
Ron Newman
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But I thought expressions such as "10/2" are compile-time constants -- the compiler evaluates them directly rather than generating code to compute them.
Why would "10/0" be different?
 
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I think it's more like the compiler substitutes the constants into the code so that it won't look up the values anymore during execution. It still evaluates the expression at runtime.
 
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