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# // Math.sqrt() question

Ranch Hand
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As per API

public static double sqrt(double a)
Returns the square root of a double value.
Parameters:
a - a double value.
Returns:
the square root of a. If the argument is NaN or less than zero, the result is NaN.

So I wrote a code

Why it is not giving me NaN for double
Can anybody explain me or give the link which explains diff. behavior for Double's Min and Max values
Megan

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Double.MIN_VALUE is not a negative number. It is the smallest positive number representable as a double.
In my opinion, the designers of Java made a mistake in using the same symbol (MIN_VALUE) to mean two quite different things for Integer vs. Double.

Sheriff
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Check out the definitions for Double.MIN_VALUE and Integer.MIN_VALUE:
static double MIN_VALUE: The smallest positive value of type double.
static int MIN_VALUE: The smallest value of type int.
So, by def'n Double.MIN_VALUE is positive, so you'll get an answer. Integer.MIN_VALUE is negative, so you'll get NaN