Printing true

[suresh kamsa]

public static void main (String[] args) {
System.out.print(Integer.MIN_VALUE == Math.abs(Integer.MIN_VALUE));
}
1. Why the output is true for Integer,Long,Double,Float.
2. The abs() should strip -ve sign for Integer,Long,Double. i.e Math.abs(Integer.MIN_VALUE)
3.Why is it stripping off -ve sign only for Short and Byte.
4. What is the value of MIN_VALUE,MAX_VALUE for Float,Double.
Thanks

[Ashish Hareet]

Hi Suresh,
The API notes the following for Math.abs(Integer.MIN_VALUE)
.....Note that if the argument is equal to the value of Integer.MIN_VALUE, the most negative representable int value, the result is that same value, which is negative.
Ditto for Long
As for Double & Float remember that Float.MIN_VALUE & Double.MIN_VALUE are positive values so you get the same result.
HTH
Ashish H.

[Isabel Wanderley]

Float.MIN_VALUE and Float.MAX_VALUE are positive??? Why they are not negative ???

[Ashish Hareet]

I'm not from a CS background ( Chem actually ) so I really take the word of the API for granted , period.
I really don't know why the makers of Java did so.Maybe someone else here can enlighten us

[Thomas Paul]

    /**
     * A constant holding the largest positive finite value of type
     * <code>float</code>, (2-2<sup>-23</sup>) ·2<sup>127</sup>.
     * It is equal to the value returned by
     * <code>Float.intBitsToFloat(0x7f7fffff)</code>.
     */
    public static final float MAX_VALUE = 3.4028235e+38f;
    /**
     * A constant holding the smallest positive nonzero value of type
     * <code>float</code>, 2<sup>-149</sup>. It is equal to the value
     * returned by <code>Float.intBitsToFloat(0x1)</code>.
     */
    public static final float MIN_VALUE = 1.4e-45f;

[ August 28, 2002: Message edited by: Thomas Paul ]