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# Ternary Operator

Greenhorn
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Please go through the following code:
public class TerOp{
public static void main(String asd[]){
int x=0;
x=(true) ? x++ : x--;
System.out.println("x= "+x);//1
}
}
It gives the value of x as 0 at line 1.
Can somebody explain why this is so?
Thanks.

Ranch Hand
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The statement
x=(true) ? x++ : x--;
can be reduced to
x = x++;
The expression x++ will return the value of x which is zero. Before the assignment operation is complete the value of x is incremented. After the increment operation is complete the previous value of x, which was zero, is assigned to x.
The following code example demonstrates that the value of x is indeed incremented before the expression is completely evaluated.

The answer is b, "Prints: 1.0".

The statement contains an addition operation. The left operand is a postfix operation and it is evaluated first. The result of the postfix operation is zero, but variable i is incremented as a side effect. The right hand operand of the addition operation is the result of method m. As a side effect, method m prints the current value of variable i which is one. Method m then returns the value zero. The result of the addition operation is zero and that is the value that is assigned to variable i.

Ranch Hand
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First <condition>? <expression1> : <expression2>
If condition is true, then expression 1 is evaluated and expression 2 is not.
x++ will use the original value of x (0) and then increment x to be equal (1)
Yet the equality operator (=) will assign the value (0) that came out of the ? : to x after all this happen, so x becomes back 0 after it was incremented to 1
if you change the x++ to ++x it will print 1
HTH

sunetra sen
Greenhorn
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Thanks guys !javascript: x()

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