Quesion from Sahir's TestCafe MockTest

[Jay Ashar]

What is the result of attempting to compile and run this code?
interface A{
void aMethod();
}
public class Test implements A{
void aMethod(){
System.out.println("hello");
}
public static void main(String[] args){
Test t = new Test();
t.aMethod();
}
}
This is the answer given:
Will fail compilation becuse the access modifier
for aMethod() is being made more restrictive.
WHY???

[Yan Bai]

Because methods in interface are implicitly public, but they don't necessarily use 'public'. So the overriding methods must declare as 'public'.
[ October 30, 2002: Message edited by: Yan Bai ]

[Jay Ashar]

makes sense... Thanks dude!!