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Precedence on Short Circuit Operators

 
Greenhorn
Posts: 12
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This is a question from Dan's Question Banks.
class A {
static boolean a; // initialized false
static boolean b; // initialized false
static boolean c; // initialized false
public static void main (String[] args) {
boolean x = (a = true) || (b = true) && (c = true);
System.out.print(a + "," + b + "," + c);
}
}
The output is true, false, false.
Doesn't the && has a higher precedence than the ||? My wrong thinking is that it should be true, true, true. How does the precedence work?
 
Author & Gold Digger
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IntelliJ IDE Java
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Please check out the following discussion which handles the very same topic:
https://coderanch.com/t/241024/java-programmer-SCJP/certification/Operator-Precedence-involving
Thanks
 
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