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method overriding and overloading

 
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the answer to this question:
If a base class has a method defined as
void method() { }
Which of the following are legal prototypes in a derived class of this class. Select the two correct answers.
a. void method() { }
b. int method() { return 0;}
c. void method(int i) { }
d. private void method() { }
Answer: A, C
[Dan changed to subject title to something more descriptive. Please use descriptive subject titles.]
[ March 03, 2003: Message edited by: Dan Chisholm ]
 
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If a base class has a method defined as
void method() { }
Which of the following are legal prototypes in a derived class of this class. Select the two correct answers.
A. void method() { }
OK. This is a legal override.
B. int method() { return 0;}
Invalid. You can't change the return type when you override a method.
C. void method(int i) { }
OK. Since the parameter list is different, method is being overloaded, not overridden.

D. private void method() { }
Invalid. You cannot narrow access to methods when overriding them.
[ March 03, 2003: Message edited by: John Paverd ]
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