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# "==" Question from Kathy's Book

Greenhorn
Posts: 8
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Given the following,
import java.awt.Button;
class CompareReference {
public static void main (String [] args){
float f = 42.0f;
float [] f1 = new float[2];
float [] f2 = new float[2];
float [] f3 = f1;
long x = 42;
f1[0] = 42.0f;
}
}
which three statements are true? (Choose three)
A. f1 == f2
B. f1 == f3
C. f2 == f1[1]
D. x == f1[0]
E. f == f1[0]
The answers are B,D and E.
The question is why D, that is why you are allow to compare a long with a float?

Ranch Hand
Posts: 93
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because of automatic numeric promotion , a long is promoted to a float and the comparison works out to true

Ranch Hand
Posts: 3271
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Preeti is right. In this case, we have what is known as binary numeric promotion. You can read all about it in the JLS, sect;5.6.2 Binary Numeric Promotion.
Corey

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