Implicit conversions...

[Brett Delia]

Why is this legal when a float is 32 bits and a long is 64 bits?
long number = 23;
float f1 = number;

[Jessica Sant]

check out this thread about the very same question:
why can a long assigned to float without casting
enjoy!

[mohana konakanchi]

The rang of long is
For long, from -9223372036854775808 to 9223372036854775807, inclusive
Where as float values can be represented with float-extened-exponent,
which in tern effectively store larger numbers than long primitive range.
java implementation automatically decides where to use float-extened-exponent or not.
In your example, it does need to use float-extened-exponenet.
for example
float f =Long.MAX_VALUE;
System.out.println(f);//will print 9.223372E18
long l=24;
f=1;
System.out.println(f);//will print 24.0

There is a enough room in float-exponential format to store all the rang of long integers.

[Jessica Sant]

There is a enough room in float-exponential format to store all the rang of long integers.
Enough to hold the range -- but not the detail. In this code snippet two very different longs get converted into the same float:

public class testLongToFloat {
   public static void main( String []args ){
      float longMax = Long.MAX_VALUE;
      System.out.println(longMax);              // prints 9.223372E18
      float longMax2 =  9223372000000000000L;
      System.out.println(longMax2);             // prints 9.223372E18
      if( longMax == longMax2 ) { System.out.println("equal"); }
      else { System.out.println("not equal"); }
   }
}