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Ranch Hand
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public class test1 {
void c(int i){
System.out.println("int");
}
void c(String s){
System.out.println("String");
}
public static void main(String[] args) {
test1 t=new test1();
char ch='p';
t.c(ch);
}
}
Why the result is :
int ??
Thanks!!
 
Greenhorn
Posts: 15
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Hi

here the "int" will be printed because the ascii value will be passed. U can print the value i to know it ..
 
Greenhorn
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Hi Peter,

This prints "int" because the when t.c(ch) is called it looks for the function with argument as Character.

char is essentially the only unsigned integral type. So when it calls invokes the first function with integer argument.

Hope this helps.
 
Greenhorn
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Thanks !!!
 
Consider Paul's rocket mass heater.
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