posted 17 years ago
Sri
Its like this
Look at the condition of the first for loop
i<x.length
x.length is the length of the x array which is clearly declared in the statement
int [][][] x=new int[3][][];
so x.length is 3, ok, so the first for loop will run for 3 times for values of i=0, i=1, i=2 ok.
Now the next for loop
for(j=0;j<x[i].length;j++)
here the condition is j shoulbe lessthan x[i].length,so
when i is zero, the condition is j<x[0].length,ok
Look at the line 5 from ur code it says
x[0]=new int [4][];
so x[0].length is 4, so the condition is j<4;
so the inner for loop will run for 4 times for j values of j=0, j=1, j=2 & j=3.now the value of i is zero.Now the sout will print 4 times ok.
Now when i=1,
the condition become j<x[1].length ie j<2 now the inner loop will run for 2 times for j values of j=0 and j=1.Now the sout will print 2 times.
Now i=2,
condition j<x[2].length ie j<5 so now the inner j loop will run for 5 times.now the sout will print 5 times.
So totally
when i=0; it prints 4 times
when i=1; it prints 2 times
when i=2; it prints 5 times
So the answer is (5+2+4) 11 times.
Hope this helps you.