[n] Strange Variable Argument behaviour?

[Nirav Patel]

Predict the output of following code.
pass 1 2 as command line arguments.

/**VarArgsDemo.java
@author Nirav
*/
import static java.lang.System.out;
public class VarArgsDemo {
public static void main(String ... bicycle) {
 
printUS(bicycle);
//out.println(bicycle instanceof String[]);
//new VarArgsDemo().printUS("on","off");
/*
printUS();
printUS("on","off");
printUS("1","2","3","4");
printUS("1");
*/
 
}
 
static void printUS(String...b) {
out.println("in printUS");
for(String s: b)
out.println(s);
}
 
static void printUS(String a1, String a2) {
out.println("Two arg printUS");
out.println(a1);
out.println(a2);
}
}

Shouldn't it be "Two arg printUS" followed by the two values?
It's not.
Answer is "in printUS" followed by the two values.
If i call

printUS("1","2")

explicitely than it calls specific method for two arg paramers but not when it's from command line.
After all here command line is also an array of

String

Any idea?

{JDK 5.0, Windows XP Pro}

TIA.
Nirav

[Nirav Patel]

Hi group!
Is there any problem with my question or am I in the wrong forum?

[Tapas Kumar]

Hi Nirav,
Acccording to my understanding vararg String ...b is equivalent to
String[] b. Before java 1.5 a developer has to explicitly move string values to an array and call the method. Java 1.5 does this for us behind the scene.
Your method call is therefore with an array reference not with two String type parameter.Result should be as you got.
Hope this helps
Tapas