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Math Class

 
Ranch Hand
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Hi to all ranchers,

While having a practice on one of the mock exams i got free over the net, I found this question confusing:

What will be the output of the code assuming embedded on a complete program.

Float f1 = new Float("4.4e99f");
Float f2 = new Float("-4.4e99f");
Double d1 = new Double("4.4e99");
System.out.println(f1);
System.out.println(f2);
System.out.println(d1);

a) Runtime error
b) Infinity
-Infinity
4.4E99
c) Infinity
-Infinity
Infinity
d) 4.4E99
-4.4E99
4.4E99

I answered D, but the correct answer says it's B. I also tried running this is my editor and it's really B. I looked for the answer explanation in the mock exam but unfortunately I got no explanation why.

Can somebody explain why the answer is B?
 
Greenhorn
Posts: 20
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I hope the answer is simple. The float range is 3.4e-038 to 3.4 e+038. So e+99 is greeater than e+38. So the float value became infinite.
 
Richard Rex
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Hi Gokul Somasundaram,

Thanks a lot! Sorry I forget to consider the range. Now it's clear to me.
 
Ranch Hand
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Ranges of float and double are xcluded from exam.I mean You won't find such questions.So Don't expect such brilliant question.
 
Ranch Hand
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Thanks agrah! That is what even i was wondering about.
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