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mock exam question

 
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Consider :
class A {}
class B extends A {}
class C extends B {}
Which of these boolean expressions correctly identifies when an object 'o' acutally refers to an object of class B and not A or C?

Select 2 correct options
a (o instanceof B) && (!(o instanceof A))
This will retrun true even if o refers to an Object of class C.

b !((o instanceof A) || (o instanceof B))


c (o instanceof B) && (!(o instanceof C))


d ! ( !(o instanceof B) || (o instanceof C))


e (o instanceof B) && !((o instanceof A) || (o instanceof C))

How the answer is c,d?

In C, if the object is of type B then it wil definitely will be instance of A.

Please clarify my doubt
 
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I think there is a logical problem with the statement of the problem. If (o instanceof B) is true, then it will always be true that (o instanceof A).
 
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a (o instanceof B) && (!(o instanceof A))
False. If o is not an instance of A, o cannot be an instance of B. Hence the right part will not be true for any instance of B. (instanceof returns true for an IS-A relationship).

b !((o instanceof A) || (o instanceof B))
False. If o is not an instance of A or B, it's not an instance of B! Couldn't be simpler.

c (o instanceof B) && (!(o instanceof C))
True. If o is an instance of B but not an instance of C, o has to be an instance of B, as any instance of C will be an instance of B (and A as well).
In C, if the object is of type B then it wil definitely will be instance of A.
Did you confuse A with C?
d ! ( !(o instanceof B) || (o instanceof C))
True. I can see why it is true for all types of o: A, B and C but what if we're talking about a 10 level hierarchy?
Anyone knows a smarter answer?

e (o instanceof B) && !((o instanceof A) || (o instanceof C))
False. Once again, an instance of B will be an instanceof A.
Sashi.
P.S. This question is highly contrived and is probably better off in a math/logic book!
 
Don't get me started about those stupid light bulbs.
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