How does it work...plz explain

[Anish Nagraj]

Plz help me in finding out how this works...

x +=x < 0 ? 2 : -2;

when i print x i get as -3

how is it?

[Christophe Verré]

what is x initialized to ?

[Anish Nagraj]

I am really soryy for not specifying the initialization value...

x is initialised to -5;

[Christophe Verré]

You have to figure out the precedence order of the operators,
and evalution order.
http://java.sun.com/docs/books/jls/second_edition/html/expressions.doc.html#4779

x = -5
x += x < 0 ? 2 : -2
x += ((x < 0) ? 2 : -2) ( x < 0, so return 2 )
x += 2
x = -5 + 2
[ March 03, 2006: Message edited by: Satou kurinosuke ]

[bnkiran kumar]

The main reason this is happening is due to that java sees that all its operands are evaluated before performing an operation.

[Anish Nagraj]

Thanks a lot...