string related question

[Amisha Shah]

program:
class strc
{
public static void main(String args[])
{
String s1="amisha";
String s2="amisha";
if(s1==s2)
{
System.out.println("same");
}
else
{
System.out.println("different");
}
}
}

in java string is an object. so when i evaluate if(s1==s2) , the test condition is evaluated as false. because both string object refers to different memory location even if contents are same. so output of this program should be different but when i run this progarm , output is same.

please tell me how this works ?

[Keith Lynn]

When you create a String literal it automatically goes into the String pool. Whenever you create another reference to the same literal it refers to the String already in the pool. A new String object is not created.

[marc weber]

See Corey McGlone's article, "Strings, Literally."

[ak pillai]

public void test(){
        String s1 = new String("A");//not recommended use String s1 = "A"
        String s2 = new String("A");//not recommended use String s2 = "A"
          
       if(s1 == s2){
           System.out.println("references are equal");
       }
       if(s1.equals(s2)){
           System.out.println("values are equal");
       }
       s1 = s2;
       if(s1 == s2){
           System.out.println("references are equal");
       } 
       
       //-------------------
       System.out.println("-------------------");
       
       String s3 = "A";//goes into String pool
       String s4 = "A";//refers to String already in the pool
       
       if(s3 == s4){
           System.out.println("references are equal");
       }
       if(s3.equals(s4)){
           System.out.println("values are equal");
       }
       s3 = s4;
       if(s3 == s4){
           System.out.println("references are equal");
       } 
    }