Arithmetic Operators

[susan waters]

class testing{
public static void main(String args[]){
int i = 3/3*6/2*6-1;
System.out.println(i);
}
}

In the above class , How should I evaluate this expression

int i = 3/3*6/2*6-1;

Tahnks for the reply

[Vladimir Scheglov]

int i = 3/3*6/2*6-1;

* and / - have same priority

3/3 = 1
than
(3/3)*6 = 6
than
((3/3)*6)/2 = 3
than
(((3/3)*6)/2)*6 = 18
than
((((3/3)*6)/2)*6) - 1 = 17

[susan waters]

thanks for the reply. So it starts evaluate from left to right ? then priority between + - and * / ? thanks

[Anupama Ponnapalli]

* and / have higher priority over + -. Within the group they are evaluated from left to right.

In the expression, - has lowest priority and separates the group into two:

[({(3/3)*6}/2)*6] minus 1

everything else has some priority and is evaluated from left to right.

[susan waters]

thanks. I understand now.