unreachable statement

[saikrishna cinux]

class Test {
public static void main ( String ka [ ] ) {
while (6>2)
{
System.out . println ( " Great " ) ;
 
}
}
};
 

why it is giving compile time error?
unreachable statement

[saikrishna cinux]

but here in these programs

  class Test {
public static void main ( String ka [ ] ) {
 
int i=5,j=10;
 
while (i<j)// here the condition is false
{
System.out . println ( " Great " ) ;
 
}
}
};
  

and see this

   
class Test {
public static void main ( String ka [ ] ) {
 

boolean b=false;
 
while (b)// here the condition is false
{
System.out . println ( " Great " ) ;
 
}
}
};
 
 

i dont know why java is making complex so i should remember each and every thing in my head before writing the exam

[wise owen]

14.21 Unreachable Statements

[Sujittt Tripathyrr]

The Program is compiles file in jdk1.4 and i am not getting any compiletime error.What is your problem. :roll:

[Ramamoorthy Periasamy]

boolean b = false;
while (b) {
System.out.println("Great"); 
}

When you change the above boolean variable b to final, then code wont compile, it says unreachable code after while.

This is because when the compiler knows the condition is false for sure (In this case we used final variable b which is compile time constant)then it will simply says anything after that statement are unreachable.

[saikrishna cinux]

Originally posted by Ramamoorthy Periasamy:

boolean b = false;
while (b) {
System.out.println("Great"); 
}

(In this case we used final variable b which is compile time constant)then it will simply says anything after that statement are unreachable.

anything means which is inside the while block not outside it
am i right..
then the compiler must skip the while block and it needs to execute the remaining part of the program after the while block.

but why it gives compile time error?
:roll: