Thread Execution

[Nilesh Patel]

   public class Test extends Thread
    {    
        public Test(String s)
        {
            super(s);
        }
 
        public void run()
        {
            System.out.println( this.getName() );
        }
 
        public static void main(String args[])   
        {
            Test t1 = new Test("0"); 
            t1.run();        
            
            Test t2 = new Test("1"); 
            t2.run();        
            
            Test th = new Test("2"); 
            th.run();
        }
 
    }

A : The output will be:
1
0
2
B : The output will be:
0
1
2
C : The output will be:
1
2
0
D : The output is unpredictable.


I think output will be "D"

Am i right??

[Mark Freeman]

If I understand my recent reading correctly, you are correct. The JVM decides which thread runs when. You can use the sleep method to *try* to control which thread runs at what time, but it is not guaranteed to work.

[Justin Yao]

Hello,
I am totally agree wiht you

[Surendra Kumar]

The output will be 0 1 2.

Note that you are not starting a new thread of execution, but just calling the method run().

To start a thread, you have to use start() method.

[prarthana reddy]

you are correct surendra. I have a question ..when we start a thread by extending the Thread class, should we not override the start method ?

[Surendra Kumar]

No. Only run() method code would run in a separate thread of execution.
start() method is to start a new thread of execution.

[Mark Freeman]

Now that was a good catch.

Originally posted by Surendra Nichenametla:
The output will be 0 1 2.

Note that you are not starting a new thread of execution, but just calling the method run().

To start a thread, you have to use start() method.

[Nilesh Patel]

yes it will 0 1 2