Can you explain this?

[sonali sawant]

Given the following code,what will be the output?

class Value
{
public int i=15;
}

public class Test
{
public static void main(String argv[])
{
Test t=new Test();
t.first();
}

public void first()
{
int i=5;
Value v=new Value();
v.i=25;
second(v,i);
System.out.println(v.i);
}

public void second(Value v,int i)
{
i=0;
v.i=20;
Value val=new Value();
v.val;
System.out.println(v.i + "" + i);
}
}

Answer is :
15 0
20

How??

[wise owen]

What is variable hiding and shadowing?

[Gowher Naik]

Above code contains compile time error at line v.val; in method named second.

[Praveen Babu]

The rule is that we cannot change the reference of an object but the object can be changed.In the method, a copy of the reference variable is passed so its changing the reference of that copy and not the actual reference.

Bye & Regards,
Praveen

[Ulf Dittmer]

You seem to be surprised by the output. Why don't you describe here what you were expecting? That would make it easier to spot were you possibly went wrong in your reasoning. It would also be a good learning experience.
[ August 22, 2006: Message edited by: Ulf Dittmer ]

[shilpa Reddy]

can someone please explain wat v.val does...i dont understand.....

[Dave Reinhardt]

The code has a compile error (somebody already mentioned this) and does not produce the output that's claimed in the original message.

valueObject1.valueObject2; //is not legal syntax as far as I know.

Where did this code come from?

[sonali sawant]

Hi,
This code is from whizlabs exam 1. Sorry i typed v.val in public void second(Value v,int i) instead of v=val. correct code is ---

public void second(Value v,int i)
{
i=0;
v.i=20;
Value val=new Value();
v=val;
System.out.println(v.i + "" + i);
}


According to me answer is---
25 0
20

We are passing second(25,5) from method first().

In method first(),
System.out.println(v.i + "" + i);
will print the value v i.e 25 and local value of i i.e 0.
and we are assigining v=val i.e v=20.

when we again come back to method first,
System.out.println(v.i);
will print 20 means answer will be
25 0
20

[ August 23, 2006: Message edited by: sonali sawant ]
[ August 23, 2006: Message edited by: sonali sawant ]

[sonali sawant]

i am really confused...

[Ulf Dittmer]

will print the value v i.e 25

v has been assigned the newly created val object, the i field of which is i=15.

Even if it hadn't been assigned val, it would not print 25, but 20, because of the "v.i = 20" assignment.
[ August 23, 2006: Message edited by: Ulf Dittmer ]

[Sruthi Sen]

Hi..

Answer is 15 0 20

First i is local variable with value 5
i.e i=5

then it creates a object v that contains i=15
ie v.i=15 (initially)

then assigning v.i=25;

so it contains 25 now..

now calling with the values like second(25,5)

here in second method
we were assigning i=0 and v.i=20

again new object val is created and val.i=15

now V=Val ie now v points to Val object so
v->val.i=15
if we say v.i,it gives 15 and as we know i=0

now control goes to first method and here v is the original object
which got modified its i value to 20 in Second method

so answer is 15 0 20

Hope you got it

Sruthi

[sonali sawant]

Thanks to all of you for explanation..now i got it.thanks.

---Sonali.