What is the sequence of execution?

[Joe San]

Hi Guys,

Consider the sample code below from Dan Chisholm,

class Sample{
static void m1(String s1) {
    s1.replace('A','Y'); System.out.print(s1);
  }
  static void m2(String s1) {
    s1 = s1.replace('A','Z'); System.out.print(s1);
  }
  public static void main(String[] s) {
    String s1 = "A"; m1(s1); m2(s1);
    System.out.print(s1);
 }
}

I want to know what will be the sequence of execution of the above code. I mean, tht static methods are executed in the order in which they are declared??am I right?? If that is the case, then with respect to the above code, m1 should execute first and what will it's parameter be?? I'm confused.

[Vinayagar Karpagam]

Did you mean that static code blocks (initializers) are always executed in the order they are written?. If not, I dont think there is anything to relate between static methods and static initializers.

[Barry Gaunt]

m1 executes first, with a String parameter value of "A".

Jothi, have you executed the code (putting in System.out.println's) and read the explanation given by Dan Chisholm?
[ December 08, 2006: Message edited by: Barry Gaunt ]

[Joe San]

Barry,

My confusion is that, we have 3 static methods. Which one will be the first one to be called at compile time and which one is the first one to be called during run time. Please anyone clarify me on this.

[Barry Gaunt]

Which one will be the first one to be called at compile time

Nothing is going to be called at compile time.

At runtime: main, m1, m2

[Barry Gaunt]

Why don't you just add a few println statements to show where you are?

class Sample2{
static void m1(String s1) {
      System.out.println("m1");  // <----------------------
      s1.replace('A','Y'); System.out.print(s1);
  }
  static void m2(String s1) {
      System.out.println("\nm2"); // <---------------------
      s1 = s1.replace('A','Z'); System.out.print(s1);
  }
  public static void main(String[] s) {
      System.out.println("main"); // <---------------------
    String s1 = "A"; m1(s1); m2(s1);
    System.out.print(s1);
 }
}    

[Joe San]

Thanks Barry.