Boxing Doubt

[Sanjeev Narula]

public class Boxing9 {
public static void main(String[] args) {
int i = 10;
method(i);
}
static void method(Object o){
System.out.println("Object called");
}
static void method(Number n){
System.out.println("Number called");
}
}


what will be answer, after boxing of primitive 'i' to Integer i. it should get widen. Since Integer is a Number and also Integer is a Object.

Which method will be called?

[Wiyanto Ngasinur]

i think the method will be called is the most specific ones.
since i is primitive int, it will be boxing to Integer... then it will called method which parameter is Number, since is the more specific than Object.

[sadasiva kumar]

Since Integer is a Number and also Integer is a Object.

Which method will be called?

Here you are passing Integer value 10 and you are not passing Object reference value.So automatically it calls the method which has Number as parameter.

[Scott Tiger]

i also think it will invoke method(Number n) this method