master exam doubt

[V Gala]

int x=0;
if(x1.hashcode()!=x2.hashcode())x=x+1;
if(x3.equals(x4)==false)x=x+10;

if(x5.equals(x6)==true)x=x+100;

if(x7.hashcode()==x8.hashcode())x=x+1000;


If o/p is 1111
which is always true
x5.hashcode()==x6.hashcode()
x3.hashcode()!=x4.hashcode()
x1.equals(x2)==true
x7.equals(x8)==true


I thinks answer should be x5.hashcode()==x6.hashcode()
but the answer was given x1.equals(x2)==true
Is answer given wrong?

[SureshKumar Sadagopal]

Could you please publish the full code, what the values of x1,x2 ... so on..

Regards
Suresh S

[John Stone]

I think you are right.

If two objects are equal according to the equals(Object) method, then 
calling the hashCode method on each of the two objects must produce the 
same integer result.

if x1.equals(x2)==true
then they should give same hashcode, but then the output can not be 1111 (you would miss 1 at the end)